: Yes, reg3 does not affect output 1 in direct way - by the argument you describe. However, reg3 affect reg1 : reg1=input+(reg2+reg3), and hence affect output 1 on the next performance cycle. [[User:Alexander Chervov|Alexander Chervov]] ([[User talk:Alexander Chervov|talk]]) 18:42, 8 October 2009 (UTC)
: I wonder if the author intended the adder above/between reg1/reg2 to add the encoder input to the reg1 output; this is based on the numerator of the first transfer function. Check my work:
* <math>reg_1=(1+reg_2+reg_3)*z^{-1},\,</math>
* <math>reg_2=reg_1*z^{-1},\,</math>
* <math>reg_3=reg_2*z^{-1},\,</math>
* combining these:
** <math>reg_1=z^{-1}+reg_1*z^{-2}+reg_1*z^{-3}=\frac{z^{-1},1-z^{-2}-z^{-3}},\,</math> <span style="font-size: smaller;" class="autosigned">—Preceding [[Wikipedia:Signatures|unsigned]] comment added by [[Special:Contributions/64.203.138.235|64.203.138.235]] ([[User talk:64.203.138.235|talk]]) 19:29, 30 November 2009 (UTC)</span><!-- Template:UnsignedIP --> <!--Autosigned by SineBot-->
