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I think the AND and OR operations are mixed up here. AND would result in 0 for all pairs except 1,1 which is the only pair with a minimum of 1, and OR is the logical operator for addition. Didn't want to change the main page b/c I don't actually know for sure if this is correct but it struck me as wrong when I saw it. -rockychat3 <span style="font-size: smaller;" class="autosigned">—Preceding [[Wikipedia:Signatures|unsigned]] comment added by [[Special:Contributions/209.94.128.120|209.94.128.120]] ([[User talk:209.94.128.120|talk]]) 04:56, 1 December 2009 (UTC)</span><!-- Template:UnsignedIP --> <!--Autosigned by SineBot-->
:<math>1</math> in position <math>(i, j)</math> in this variant of the algorithm means that we already know that there is a path between vertices <math>i</math> and <math>j</math>. If you want to combine paths <math>i \rightarrow k</math> and <math>k \rightarrow j</math> (where you would use addition of their lengths in the usual variant), you have to use AND (you can go from <math>i</math> to <math>j</math> through <math>k</math> if there is a path between <math>i</math> and <math>k</math> AND there is a path between <math>k</math> and <math>j</math>). When you try to decide whether there is path through <math>k</math> OR “direct” (i.e. one we already know) path, you use OR. The difference stems from the fact that “no path” is represented as infinity in the usual algorithm, but as <math>0</math> in this variant. [[User:Svick|Svick]] ([[User talk:Svick|talk]]) 11:31, 1 December 2009 (UTC)
== Python code? ==
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