Continuous embedding: Difference between revisions

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:Then, for every ''n'', ||''f''<sub>''n''</sub>||<sub>''Y''</sub>&nbsp;=&nbsp;||''f''<sub>''n''</sub>||<sub>&infin;</sub>&nbsp;=&nbsp;''n'', but
 
::<math>\| ff_{n} \|_{L^{1}} = \int_{0}^{1} | f_{n} (x) | \, \mathrm{d} x = \frac1{2}.</math>
 
:Hence, no constant ''C'' can be found such that ||''f''<sub>''n''</sub>||<sub>''Y''</sub>&nbsp;&le;&nbsp;''C''||''f''<sub>''n''</sub>||<sub>''X''</sub>, and so the embedding of ''X'' into ''Y'' is discontinuous.