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Line 31:
<math>z^3+27=(z+3)(z^2-3z+9),</math><br />
<br />or<br /><br />
<math>8x^3+125=(2x)^3+(5)^3=(2x+5)[(2x)^2-(5)(2x)+(5)^2]=(2x+5)(4x^2-10x+
<br /><br />
|
Line 31:
<math>z^3+27=(z+3)(z^2-3z+9),</math><br />
<br />or<br /><br />
<math>8x^3+125=(2x)^3+(5)^3=(2x+5)[(2x)^2-(5)(2x)+(5)^2]=(2x+5)(4x^2-10x+
<br /><br />
|