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→Algorithm: The previous iterates give the decimal expansion to the first incorrect digit, so I'm continuing the pattern |
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:<math>\sum_{i=0}^\infty 2^{i-1} c_i^2 = 1 - {E(\sin\varphi)\over K(\sin\varphi)}\!</math>
where <math>E(k)\!</math>
:<math>E(k) = \int_0^{\pi/2}\sqrt {1-k^2 \sin^2\theta}\, d\theta.\!</math>
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