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and dividing both sides by <math>\Delta x \Delta y</math>
: <math>\frac{E_x(y+\Delta y)-E_x(y)}{\Delta y}-\frac{E_y(x+\Delta x)-E_y(x)}{\Delta x} = 2L'\Delta l\frac{\partial{I}}{\partial{t}}*1\frac{{\Delta x}{\Delta y}}</math>
Since <math>\Delta x = \Delta y = \Delta z = \Delta l</math> and substituting <math>I = H_z \Delta z</math> gives
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