Integration using Euler's formula: Difference between revisions

Revision as of 18:38, 26 May 2010

Revision as of 12:27, 16 August 2010

Line 21:

\frac{1}{4}\int \left( e^{2ix} + 2 + e^{-2ix} \right) dx

\,&=\, \frac{1}{4}\left(\frac{e^{2ix}}{2i} + 2x - \frac{e^{-2ix}}{2i}\right)+C \\[6pt]

&=\, \frac{1}{4}\left(2x + \sin 2x\right) +C.

\end{align}</math>

Of course, this example is so simple that it's not very difficult to handle with standard trigonometric identities.

==Second example==