Circular segment: Difference between revisions

Revision as of 13:50, 29 January 2006

Revision as of 18:50, 9 February 2006

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<math>R^2\left(\frac{\theta}{2}-\sin\frac{\theta}{2}\cos\frac{\theta}{2}\right)</math>

According to trigonometry, '''<big><math>2\sin x \cos x = 2\sin x\cos x=2\sin x2x</math></big>''', therefore

<math>\sin\frac{\theta}{2}\cos\frac{\theta}{2} = \frac{1}{2}\sin\theta</math>