Talk:Lyapunov function: Difference between revisions

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== Example ==
 
In the given example, in the development of the expression for <math>\dot V(x)</math>, shouldnwouldn't thereit be abetter to replace the <math>\dot f(x)</math> instead ofby a <math>f(\dot x)</math> (according to the [[chain rule]])? TheI completeunderstand equation would be:that <math>\dot Vf(x) = V'(x) \dot x = \mathrm{sign}(x)\cdot (-x) = -|x|<0.</math>, but since <smallmath><span\dot class="autosigned"x</math> Precedingcomes [[Wikipedia:Signatures|unsigned]]directly commentfrom added bythe [[User:Guissoares|Guissoares]]chain ([[User talk:Guissoares|talkrule]], I [[Special:Contributions/Guissoares|contribs]])think 21:53,the 7steps Januarywould 2011be (UTC)</span></small><!--clearer Template:Unsignedand -->more <!--Autosignednatural bythat SineBot-->way.
The complete equation would be: <math>\dot V(x) = V'(x) \dot x = \mathrm{sign}(x)\cdot (-x) = -|x|<0.</math>