One feasible solution is to assign the sea vessel and one aircraft to the highest valued target (3). This results in an expected survival value of <math> 3020(0.6)(0.5)= 96 </math>. One could then assign the remaining aircraft and 2 tanks to target #2, resulting in expected survival value of <math> 2010 (0.4)(0.8)^2 = 2.04856 </math>. Finally, the remaining 3 tanks are assigned to target #1 which has an expected survival value of <math> 5 (0.7)^3 = 1.715 </math>. Thus, we have a total expected survival value of <math> 96 + 2.04856 + 1.715 = 1210.763275 </math>.
