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Every simple ''R''-module is isomorphic to a quotient ''R''/''m'' where ''m'' is a [[maximal ideal|maximal right ideal]] of ''R''.<ref>Herstein, ''Non-commutative Ring Theory'', Lemma 1.1.3</ref> By the above paragraph, any quotient ''R''/''m'' is a simple module. Conversely, suppose that ''M'' is a simple ''R''-module. Then, for any non-zero element ''x'' of ''M'', the cyclic submodule ''xR'' must equal ''M''. Fix such an ''x''. The statement that {{nowrap begin}}''xR'' = ''M''{{nowrap end}} is equivalent to the surjectivity of the homomorphism {{nowrap|''R'' → ''M''}} that sends ''r'' to ''xr''. The kernel of this homomorphism is a right ideal ''I'' of ''R'', and a standard theorem states that ''M'' is isomorphic to ''R''/''I''. By the above paragraph, we find that ''I'' is a maximal right ideal. Therefore ''M'' is isomorphic to a quotient of ''R'' by a maximal right ideal.
If ''k'' is a [[field (mathematics)|field]] and ''G'' is a [[group (mathematics)|group]], then a [[group representation]] of ''G'' is a [[left module]] over the [[group ring]] ''
== Basic properties of simple modules ==
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