Content deleted Content added
Jitse Niesen (talk | contribs) →Adams–Moulton methods: correct link |
Jitse Niesen (talk | contribs) →Definitions: copy-edit, mainly removing redundancy |
||
Line 7:
The result is approximations for the value of <math> y(t) </math> at discrete times <math> t_i </math>:
: <math> y_i \approx y(t_i) \quad\text{where}\quad t_i = t_0 + i h, </math>
where ''h'' is the time step (sometimes referred to as <math> \Delta t </math>).
: <math> \begin{align}
& y_{n+s} + a_{s-1} y_{n+s-1} + a_{s-2} y_{n+s-2} + \cdots + a_0 y_n \\
& \qquad {} = h \bigl( b_s f(t_{n+s},y_{n+s}) + b_{s-1} f(t_{n+s-1},y_{n+s-1}) + \cdots + b_0 f(t_n,y_n) \bigr),
\end{align} </math>
One can distinguish between [[explicit and implicit methods]]. If <math> b_s = 0 </math>, then the method is called "explicit", since the formula can directly compute <math> y_{n+s} </math>. If <math> b_s \ne 0 </math> then the method is called "implicit", since the value of <math>y_{n+s}</math> depends on the value of <math> f(t_{n+s}, y_{n+s}) </math>, and the equation must be solved for <math> y_{n+s} </math>. [[Iterative methods]] such as [[Newton's method]] are often used to solve the implicit formula.
Sometimes an explicit multistep method is used to "predict" the value of <math>y_{n+s}</math>. That value is then used in an implicit formula to "correct" the value. The result is a [[
==Examples==
|