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Line 13: Case1: If 'n' is odd then p should be (n(n-4) + 7)/4 and q should be (n(n+4) + 7)/4 Case2: If 'n' is even & m = n/2 is odd then p should be (m(m -2) + 2) and q should be (m(m + 2) + 2) Case3: If 'n' is even & m = n/2 is also even then p should be (m - 1)^2 and q should be (m + 1)^2

Talk:Fermat's factorization method: Difference between revisions