Content deleted Content added
m removed interwiki to nl |
|||
Line 20:
:In general, the function remains the same for every [[permutation]] of its variables. This means that, in this case,
::<math> (x-x_1)(x-x_2)(x-x_3)=(x-x_2)(x-x_1)(x-x_3)=(x-x_3)(x-x_1)(x-x_2)
:and so on, for all permutations of <math>x_1,x_2,x_3</math>
|