Alternating sign matrix: Difference between revisions

Revision as of 11:54, 7 March 2013

Revision as of 05:07, 30 March 2013

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\prod_{k=0}^{n-1}\frac{(3k+1)!}{(n+k)!} = \frac{1! 4! 7! \cdots (3n-2)!}{n! (n+1)! \cdots (2n-1)!}.

</math>

The first few ternterms in this seriessequence for ''n'' = 0, 1, 2, 3, … are

:[[1 (number)|1]], 1, [[2 (number)|2]], [[7 (number)|7]], [[42 (number)|42]], 429, 7436, 218348, … {{OEIS|id=A005130}}.