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:<math>0 = c^T\left(\left(\sum_{i=1}^t \lambda_i x_i\right)-x^\ast\right) = c^T\left(\sum_{i=1}^t \lambda_i (x_i - x^\ast)\right) = \sum_{i=1}^t \lambda_i (c^Tx_i - c^Tx^\ast)</math>
Since all terms in the sum are
==References==
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