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Is this algorithm right? I'm not an expert, but when I compare it to the online variance computation, it's different, and if I replace y with x, I should get cov(x,x) = var(x), so could anyone have a look please? [[Special:Contributions/131.227.95.222|131.227.95.222]] ([[User talk:131.227.95.222|talk]]) 18:03, 27 February 2013 (UTC)
: Alright, I found a paper talking about this and now I understand that the formula is talking about co-moments and not covariances, I will add the note to the article. [[Special:Contributions/131.227.95.222|131.227.95.222]] ([[User talk:131.227.95.222|talk]]) 10:31, 28 February 2013 (UTC)
== Merge discussion ==
There was a merge tag added at [[Standard deviation#Rapid calculation methods]] to this article. I think it is quite reasonable to have that section be a summary of this article. I must admit I was rather surprised I couldn't find a version of the <math>\operatorname{E}\left[(X-\operatorname{E}(X))^2\right] = \operatorname{E}\left[X^2 \right] - (\operatorname{E}[X])^2</math> formula in the standard deviation article, I've put a bit in its talk page about that and that that article is slow referring to variance and never links to it.
For this article as old speedup calculation method is at [[assumed mean]]. [[User:Dmcq|Dmcq]] ([[User talk:Dmcq|talk]]) 09:19, 17 May 2013 (UTC)
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