Differential dynamic programming: Difference between revisions

Content deleted Content added
Line 136:
\begin{align}
\hat{\mathbf{x}}(1)&=\mathbf{x}(1)\\
\hat{\mathbf{u}}(i)&=\mathbf{u}(i) + \mathbf{k}(i) +\mathbf{K}(i)(\hat {\mathbf{x}}(i) - \mathbf{x}(i))\\
\hat{\mathbf{x}}(i+1)&=\mathbf{f}(\hat {\mathbf{x}}(i),\hat {\mathbf{u}}(i))
\end{align}
</math>