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:<math> \begin{align} a_{n+1} & = \frac{a_n + b_n}{2}, \\
b_{n+1} & = \sqrt{a_n b_n}, \\
t_{n+1} & = t_n
p_{n+1} & = 2p_n.
\end{align}
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3. π is then approximated as:
The first three iterations give (approximations given up to and including the first incorrect digit):
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