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lim (Σ<sub>n</sub> n<sup>m</sup>)/n<sup>m+1</sup> = 1/(m+1) for each m of N
<sup>n→∞ </sup><sup>1</sup>
Note that the inverse limit (zero to infinity) diverges, reproducing the sequence of natural numbers.
:::Can anyone tell me if it's new? --[[User:Ancora Luciano|Ancora Luciano]] ([[User talk:Ancora Luciano|talk]]) 07:41, 26 May 2013 (UTC)
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