Integration using Euler's formula: Difference between revisions

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m Reverted edits by 204.126.64.99 (talk) to last version by Alizter
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\frac{1}{4}\int \left( e^{2ix} + 2 + e^{-2ix} \right) dx
\,&=\, \frac{1}{4}\left(\frac{e^{2ix}}{2i} + 2x - \frac{e^{-2ix}}{2i}\right)+C \\[6pt]
&=\, \frac{1}{4}\left(2x + \sin x2x\right) +C.
\end{align}</math>