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:Both formulas have the same meaning, namely '''J'''<sup>T</sup>'''Jq''' + λ'''q''' = −'''J'''<sup>T</sup>'''f'''. As far as I am concerned, it is a matter of taste which you prefer, but the second is perhaps clearer. -- [[User:Jitse Niesen|Jitse Niesen]] ([[User talk:Jitse Niesen|talk]]) 20:46, 30 August 2005 (UTC)
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All formulas have a lack of negative sign. For example:
:<math>\mathbf{(J^{T}J)\boldsymbol \delta = J^{T} [y - f(\boldsymbol \beta)]} \!</math>
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finding this bug took quite some time. And it should be pointed out, how to get to this formula. --vogt31337 9:00 26 January 2012 (UTC) <small><span class="autosigned">— Preceding [[Wikipedia:Signatures|unsigned]] comment added by [[User:Vogt31337|Vogt31337]] ([[User talk:Vogt31337|talk]] • [[Special:Contributions/Vogt31337|contribs]]) </span></small><!-- Template:Unsigned --> <!--Autosigned by SineBot-->
@ Vogt31337:
i think there is no sign missing since '''J''' is the jacobian of '''f''' and '''f''' has a negativ sign in '''S'''. the goal is to minimize '''S''' and therefore we want to go in direction of negativ jacobian of
'''S''' which turns out to be the negative jacobian of '''-f''' and thus '''-(-J) = J'''. -- Georg
==Transpose==
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