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<math>Ave_{n}\Lambda_{A}(m)=log(q)</math>.
*Define [[Euler totient function]] polynomial analogue, <math>\Phi</math>, to be the number of elements in the group <math>(A/fA)^{*}</math>. We have,
<math>\sum_{\text{deg}f=n, f\text{monic}}\Phi(f)=q^{2n}(1-q^{-1})</math>
==See also==
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