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Line 49: The method for solving this equation relies on a special integrating factor, ''μ'': :<math>\mu = e^{\~~int~~int_{x_0}^x p(xt)\, dxdt}</math> We choose this integrating factor because it has the special property that its derivative is itself times the function we are integrating, that is: :<math>\frac{d{\mu}}{dx} = e^{\~~int~~int_{x_0}^x p(xt)\, dxdt} \cdot p(x) = \mu p(x)</math> Multiply both sides of the original differential equation by ''μ'' to get:

Examples of differential equations: Difference between revisions