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\left( 2\,iz+\pi \right) {\it HeunB} \left( 2,0,0,0,\sqrt {2}\sqrt {
1/2\,i\pi -z} \right) {{\rm e}^{2\,z-1/2\,i\pi }}}}</math>
*<math>tanhc(z)={\frac {i{{\rm \bf WhittakerM}\left(0,\,1/2,\,2\,z\right)}}{
{{\rm \bf WhittakerM}\left(0,\,1/2,\,i\pi -2\,z\right)}z}}</math>
==Gallery==
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