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In [[electrodynamics]], '''elliptical polarization''' is the [[polarization]] of [[electromagnetic radiation]] such that the tip of the [[electric field]] [[Vector (spatial)|vector]] describes an [[ellipse]] in any fixed plane intersecting, and [[Surface normal|normal]] to, the direction of propagation. An
▲Example <p>
The angle between the electric field vector and the '''x''' axis is given by
:<math>\Phi(\mathbf{E})=\tan^{-1}{E_y\over E_x},</math>
where <math>E_x</math> and <math>E_y</math> are perpendicular [[vector component|components]] of the electric field vector. If the x and y components have a 90° phase shift between them, these components are given by
:<math>E_y=E_{yo} \sin(wt+\phi),\ \mathrm{and}\,</math>
:<math>E_x=E_{xo} \sin(wt+\phi+{\pi \over 2}),</math>
where <math>\phi\,</math> is an arbitrary phase, and <math>E_xo</math> and <math>E_yo</math> are the [[amplitude]]s of the x and y components of the field. It can then be shown that
:<math>\Phi(\mathbf{E}) = \omega t,</math>
which indicates that the electric field vector
{{optics-stub}}▼
[[Category:Polarization]]
[[ja:楕円偏光]]
▲{{optics-stub}}
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