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"::show()" means qualified name, and that's why according to standard the lookup must not search the implementation above, and that's why clang fail with this example, while g++ not (misbehaviour) |
Progers1618 (talk | contribs) m Remove extra space:"friend void show(" -> "friend void show(" |
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Line 32:
public:
Foo(): b(6) {}
friend void
friend void Bar::show(Bar& x, Foo& y); // declaration of friend from other class
};
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