Elliptical polarization: Difference between revisions

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where <math>\phi\,</math> is an arbitrary phase, and <math>E_xo</math> and <math>E_yo</math> are the [[amplitude]]s of the x and y components of the field. It can then be shown that
:<math>\Phi(\mathbf{E}) = \omega t,</math>
which indicates that the electric field vector rotates with an [[angular velocity]] <math>\omega</math>. Since the phase shift on <math>E_x</math> is positive, the rotation is counterclockwise. If <math>E_{yo} = E_{xo}</math>, the polarization is circular. If they are different, it is elliptical.
 
==See also==
*[[Polarization of classical electromagnetic waves]]
*[[Linear polarization]]
*[[Circular polarization]]
 
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