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For each <math>i \in \{1, \dots, n\}</math>:
# Pick <math>j \in \{0, \dots, 2^n-1\}</math>
# Pick <math>k \in \{0, \dots, 2^n-1\}</math> such that <math>j+k = e_i</math> where <math>j+k</math> is the bitwise ''xor'' of <math>j</math> and <math>k</math>.
# <math>x_i \gets y_j+y_k</math>
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