Talk:Algorithms for calculating variance: Difference between revisions

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Algorithm III
Algorithm III: ignore my previous comment
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I'm pretty sure this is wrong. From Welford's Paper:
 
S[n]=S[n-1]+(n-1)/n*(x[n]-mean[n-1])^2
 
--[[User:Cfp|cfp]] 21:58, 15 August 2006 (UTC)
 
:I'm talking rubbish it's fine as x[n]-mean[n] = (n-1)/n*(x[n]-mean[n-1]). Sorry! --[[User:Cfp|cfp]] 22:20, 15 August 2006 (UTC)