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Line 44: ===Dirichlet series=== ~~Moreover,~~ The L-function of completely (or totally) [[multiplicative function\|multiplicative]] [[Dirichlet series]] a(n) satisfies :<math>L(s,a)=\sum^\infty_{n=1}\frac{a(n)}{n^s}=\prod_p\biggl(1-\frac{a(p)}{p^s}\biggr)^{-1},</math> which means that the sum all over the natural numbers is equal to the product all over the prime numbers.

Completely multiplicative function: Difference between revisions