Liu Hui's π algorithm: Difference between revisions

Content deleted Content added
m clean up, typo(s) fixed: Therefore → Therefore,; Realigned see also section using AWB
Line 127:
In which
 
: <math> F = \tfrac{1}{4} + \left(\tfrac{1}{4}\right)^2 + \left(\tfrac{1}{4}\right)^3 + \left(\tfrac{1}{4}\right)^4 + \cdots = \frac{\frac{1}{4}}{1-\frac{1}{4}}=\tfrac{1}{3}.</math>
 
That is all the subsequent excess areas add up amount to one third of the <math>D_{192}</math>