Uniqueness theorem for Poisson's equation: Difference between revisions

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0</math>

The boundary conditions for which the above is true areinclude:

# [[Dirichlet boundary condition]]: <math>\varphi</math> is well defined at all of the boundary surfaces. As such <math>\varphi_1=\varphi_2</math> so at the boundary <math>\phi = 0</math> and correspondingly the surface integral vanishes.