Data processing inequality: Difference between revisions

Revision as of 09:48, 6 June 2017

Revision as of 09:48, 6 June 2017

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==Example==

Let <math>X \rightarrow Y \rightarrow Z</math> be a [[Markov chain]].; then,<br>

<br>

Then,<br>

<math> I(x;y) \geqslant I(x;z)</math> with <br>

<math>I(x;y) = I(x;z)</math> if and only if <math>X \rightarrow Z \rightarrow Y</math><br>