Normalizing constant: Difference between revisions

Revision as of 17:04, 9 December 2016

Revision as of 16:14, 3 March 2018

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we have

:<math>\int_{-\infty}^\infty p(x)\,dx=\int_{-\infty}^\infty e^{-x^2/2}\,dx=\sqrt1÷sqrt{2\pi\,},</math>

if we define a function <math> \varphi(x) </math> as