Pollard's rho algorithm for logarithms: Difference between revisions

Content deleted Content added
Fixing the code example
Algorithm: Use less painful typography for modulo.
Line 21:
g(x,n) &= \begin{cases}
n & x\in S_0\\
2n \ (\bmod \pmod p) & x\in S_1\\
n+1 \ (\bmod \pmod p) & x\in S_2
\end{cases}
\\
h(x,n) &= \begin{cases}
n+1 \ (\bmod \pmod p) & x\in S_0\\
2n \ (\bmod \pmod p) & x\in S_1\\
n & x\in S_2
\end{cases}