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The algorithm compares successive characters of <code>W</code> to "parallel" characters of <code>S</code>, moving from one to the next by incrementing <code>i</code> if they match. However, in the fourth step <code>S[3] = ' '</code> does not match <code>W[3] = 'D'</code>. Rather than beginning to search again at <code>S[1]</code>, we note that no <code>'A'</code> occurs between positions 1 and 2 in <code>S</code>; hence, having checked all those characters previously (and knowing they matched the corresponding characters in <code>
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