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Grammatica gecorrigeerd Tags: Mobile edit Mobile app edit |
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:<math>
\begin{align}
& =\frac{\mathbb{P}(Y_{i1}=1|X_{i1}) \mathbb{P}(Y_{i2}=0|X_{i2})}{\mathbb{P}(Y_{i1}=1|X_{i1}) \mathbb{P}(Y_{i2}=0|X_{i2})+\mathbb{P}(Y_{i1}=0|X_{i1}) \mathbb{P}(Y_{i2}=1|X_{i2})}\\[6pt] \ & =\frac{\frac{\exp(\alpha_i+\boldsymbol{\beta}^\top X_{i1})}{1+\exp(\alpha_i+\boldsymbol{\beta}^\top X_{i1})}\times\frac{1}{1+\exp(\alpha_i+\boldsymbol{\beta}^\top X_{i2})}}{\frac{\exp(\alpha_i+\boldsymbol{\beta}^\top X_{i1})}{1+\exp(\alpha_i+\boldsymbol{\beta}^\top X_{i1})}\times\frac{1}{1+\exp(\alpha_i+\boldsymbol{\beta}^\top X_{i2})}+\frac{1}{1+\exp(\alpha_i+\boldsymbol{\beta}^\top X_{i1})}\times\frac{\exp(\alpha_i+\boldsymbol{\beta}^\top X_{i2})}{1+\exp(\alpha_i+\boldsymbol{\beta}^\top X_{i2})}}\\[6pt]
\ & =\frac{\exp(\boldsymbol{\beta}^\top X_{i1})}{\exp(\boldsymbol{\beta}^\top X_{i1})+\exp(\boldsymbol{\beta}^\top X_{i2})}. \\[6pt]
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