Functional integration: Difference between revisions

Revision as of 13:29, 19 September 2018

Revision as of 19:17, 28 December 2018

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</math>

By functionally differentiating this with respect to ''J''(''x'') and then setting ''J'' to 0 this becomes an exponential multiplied by a polynomial in ''f''. For example, setting <math>K(x, y) = \Box\delta(x - y)</math>, we find:

:<math>