Functional determinant: Difference between revisions

Content deleted Content added
m Typo fixing, replaced: an Harmonic oscillator → a Harmonic oscillator, as in the linked article.
The infinite potential well: n=0 is no eigenvalue, the corresponding „eigenstate“ would be the null vector
Tags: Mobile edit Mobile web edit
Line 73:
where ''A'' is the depth of the potential and ''L'' is the length of the well. We will compute this determinant by diagonalizing the operator and multiplying the [[eigenvalue]]s. So as not to have to bother with the uninteresting divergent constant, we will compute the quotient between the determinants of the operator with depth ''A'' and the operator with depth ''A'' = 0. The eigenvalues of this potential are equal to
 
:<math> \lambda_n = \frac{n^2\pi^2}{L^2} + A \qquad (n \in \mathbb N_0N). </math>
 
This means that