Punctured code: Difference between revisions

Revision as of 13:41, 5 February 2019

Revision as of 05:14, 7 February 2019

Line 14:

2011.

</ref>

==== Python example ====

<source lang="python">

import numpy as np

def puncturing(message, punct_vec):

shift = 0

N = len(punct_vec)

punctured = []

for idx, item in enumerate(message):

if punct_vec[idx-shift*N] == 1:

punctured.append(item)

if idx%N == 0:

shift = shift + 1

return np.array(punctured)

def depuncturing(punctured, punct_vec, shouldbe):

shift = 0

shift2 = 0

N = len(punct_vec)

depunctured = np.zeros((shouldbe,))

for idx, item in enumerate(depunctured):

if punct_vec[idx - shift*N] == 1:

depunctured[idx] = float(punctured[idx-shift2])

else:

shift2 = shift2 + 1

if idx%N == 0:

shift = shift + 1;

return depunctured

message = np.array([1, 2, 3, 4, 5, 6, 7, 8])

punct_vec = np.array([1, 1, 0])

punctured = puncturing(message, punct_vec)

print(punctured)

depunctured = depuncturing(punctured, punct_vec, len(message))

print(depunctured)

</source>

==See also==