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:<math>\boldsymbol{L}_{xy}f(x,y)=0,</math>
where <math>\boldsymbol{L}_{xy}</math> is a linear operator which contains derivatives with respect to {{mvar|x}} and {{mvar|y}}, subject to the mixed conditions on {{mvar|y}} = 0, for some prescribed function {{math|''g''(''x'')}},
:<math>f=g(x)\text{ for }x\leq 0, \quad
and decay at infinity i.e. {{mvar|f}} → 0 as <math>\boldsymbol{x}\rightarrow \infty</math>.
Taking a [[Fourier transform]] with respect to {{mvar|x}} results in the following [[ordinary differential equation]]
: <math>\boldsymbol{L}_y \widehat{f}(k,y)-P(k,y)\
where <math>\boldsymbol{L}_{y}</math> is a linear operator containing {{mvar|y}} derivatives only, {{math|''P''(''k,y'')}} is a known function of {{mvar|y}} and {{mvar|k}} and
: <math> \widehat{f}(k,y)=\int_{-\infty}^\infty f(x,y)e^{-ikx} \, \textrm{d}x. </math>
If a particular solution of this ordinary differential equation which satisfies the necessary decay at infinity is denoted {{math| ''F''(''k'',''y'')}}, a general solution can be written as
: <math> \
where {{math|''C''(''k'')}} is an unknown function to be determined by the boundary conditions on {{mvar|y}}=0.
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: <math> \widehat{g}(k)+\widehat{f}_{+}(k,0) = \widehat{f}_{-}(k,0)+\widehat{f}_{+}(k,0) = \widehat{f}(k,0) = C(k)F(k,0) </math>
and, on taking derivatives with respect to <math>y</math>,
: <math> \
Eliminating <math>C(k)</math> yields
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