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==Square roots and cube roots==
The process of extracting the [[square root]] in balanced ternary is analogous to that in decimal or binary.
:<math>(10\cdot x+y)^{\mathrm{1T}}-100\cdot x^{\mathrm{1T}}=\mathrm{1T0}\cdot x\cdot y+y^{\mathrm{1T}}=
\begin{cases}
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