Common integrals in quantum field theory: Difference between revisions

Revision as of 13:42, 18 December 2019

Revision as of 19:37, 28 January 2020

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Completing the square

:<math> \left( {1 \over 2} i a x^2 + iJx\right ) = {1\over 2} ia \left ( x^2 + {2Jx \over a} + \left ( { J \over a} \right )^2 - \left ( { J \over a} \right )^2 \right ) = -{1\over 2} {a \over i} \left ( x + {J\over a} \right )^2 - { iJ^2 \over 2a}. </math>

By analogy with the previous integrals