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{{db|still no context to this article, so I believe this can be speedied under A1. Also, recreation of earlier speedily deleted article, so please protect}}
{{Importance|date=December 2006}}
{{incoherent}}<!--I can't find a better tag to say "This is in jargon; please rewrite in English prose.-->
At the beginning we let take X ,Y ,z as complex numbers :-
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:<math> x^{y} = (r e^{i\theta})^{(k e^{i\varphi})} = e^{k[(\cos(\varphi) \ln(r)+ \sin(\varphi) \theta)+ i (\cos(\varphi) \theta - \sin(\varphi)\ln(r))]} \,</math>
==The Proof==
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we return y to the poler form by sub <math>A=k \cos(\varphi)</math> , <math>sub B=k \sin(\varphi)</math> . then we get....
:<math> x^{y} = (r e^{i\theta})^{(k e^{i\varphi})} = e^{k[(\cos(\varphi) \ln(r)+ \sin(\varphi) \theta)+ i (\cos(\varphi) \theta - \sin(\varphi)\ln(r))]} \,</math>
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