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{{DISPLAYTITLE:''n''th root algorithm}}
The [[Principal branch|principal]] [[nth root|''n''th root]] <math>\sqrt[n]{
==Using Newton's method==
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The ''n''<sup>th</sup> root problem can be viewed as searching for a zero of the function
:<math>f(x) = x^n -
So the derivative is
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:<math>x_{k+1} = x_k - \frac{f(x_k)}{f'(x_k)}</math>
:<math> = x_k - \frac{x_k^n -
:<math> = x_k + \frac{1}{n} \left[-x_k +\frac{
:<math> = \frac{1}{n} \left[{(n-1)x_k +\frac{
==See also==
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