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Line 84: for the divisor function of zeroth order <math> \sum_{n=1}^\infty \sigma_0 (n) f(n) = \sum_ {m=-\infty}^\infty \sum_{n=1}^\infty f(mn) </math> using a test function of the form $$math f(xe^{x})e^{ax} $$\math for some positive 'a' turns the poisson summation formula into a formula involving the Mellin transform ==Generalizations==

Explicit formulae for L-functions: Difference between revisions