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===Cycle===
Cycles are also easier than in the unlabelled case. A cycle of length <math>k</math> corresponds to <math>k</math> distinct sequences. Thus for <math>\mathcal{A} = \mathfrak{C}\{\mathcal{B}\}</math>, we have
:<math>A(z) = \sum_{k = 0}^{\infty} \frac{B(z)^k}{k} = \ln\left(\frac{1}{1-B(z)}\right).</math>
===Other elementary constructions===
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