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→A function with a unique fixed point: Graph must be closed |
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Line 50:
\varphi(x)=
\begin{cases}
3/4 & 0 \le x < 0.5 \\{}
1/4 & 0.5 < x \le 1
\end{cases}
</math>
satisfies all Kakutani's conditions, and indeed it has a fixed point: ''x'' = 0.5 is a fixed point, since ''x'' is contained in the interval
===A function that does not satisfy convexity===
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