Paavono

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Wikipedia:Babel
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${\displaystyle \sum _{p=1}^{n}p^{2}=1^{2}+2^{2}+3^{2}+...+n^{2}={\frac {n(n+1)(2n+1)}{6}}}$

${\displaystyle \sum _{p=1}^{n}(p^{2})+(n+1)^{2}=\sum _{p=1}^{n+1}p^{2}}$

${\displaystyle \sum _{p=1}^{n+1}p^{2}={\frac {(n+1)(n+2)(2(n+1)+1)}{6}}={\frac {(n^{2}+3n+2)(2n+3)}{6}}}$

${\displaystyle \sum _{p=1}^{n}(p^{2})+(n+1)^{2}={\frac {2n^{3}+9n^{2}+13n+6}{6}}}$

${\displaystyle \ Q.E.D.}$